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9x^2-12x-15=10
We move all terms to the left:
9x^2-12x-15-(10)=0
We add all the numbers together, and all the variables
9x^2-12x-25=0
a = 9; b = -12; c = -25;
Δ = b2-4ac
Δ = -122-4·9·(-25)
Δ = 1044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1044}=\sqrt{36*29}=\sqrt{36}*\sqrt{29}=6\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6\sqrt{29}}{2*9}=\frac{12-6\sqrt{29}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6\sqrt{29}}{2*9}=\frac{12+6\sqrt{29}}{18} $
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